Skip to content
induwara.lk
induwara.lkSri Lanka · Construction

Sri Lanka Brick & Block Wall Material Calculator

Enter a wall's length, height and unit size and get the exact number of cement blocks or bricks, 50 kg cement bags, and cubes of sand it needs, with your mortar mix and wastage built in. No signup, sources cited below.

By Induwara AshinsanaUpdated Jul 11, 2026
Wall material estimatebricks · blocks · cement · sand
SLS · CIDA method
Quick start

Total area of openings. Leave at 0 for a solid wall.

SLS 855 face size, 200 mm (8″) thick, common boundary wall block

One skin of units, the usual boundary / partition wall.

Typical block & brick walls

Add prices for a cost estimate (optional)
Rs
Rs
Rs
Blocks
366
Wastage included, rounded up
Cement (50 kg bags)
3
1:5 (common) mortar
Sand (cubes)
0.17
0.48 m³ · ~774 kg
blocks/m²
11.6
Net face: 30 m²
Net wall face area30 m² (322.92 ft²)
Finished wall thickness200 mm
Gross wall volume6 m³
Dry mortar volume0.58 m³
Cement volume0.1 m³
Sand volume0.48 m³ (0.17 cube)

Shopping list

Wall material list, induwara.lk
Wall: 30 m² face, single leaf
366 blocks (Cement block: 400 × 200 × 200 mm)
3 × 50 kg cement bags (1:5 (common))
Sand: 0.17 cube (0.48 m³)

Cement quantity verified two ways, by 50 kg bag volume (0.0347 m³) and by cement mass (1440 kg/m³). Both agree.

Unit sizes follow SLS 855 (cement blocks) and SLS 39 (clay bricks). Mortar quantities use the volumetric method with CIDA's 1.30 dry-volume factor; one 50 kg cement bag = 0.0347 m³, one cube of sand = 2.832 m³.

How it works

This calculator turns a wall's geometry into a material list using the standard volumetric mortar method, the same approach behind CIDA's rate analysis and IS 2212 for brickwork. Everything is computed in metres internally (1 ft = 0.3048 m).

  1. Net face area. Wall length × height, minus the area of any doors or windows: A = L × H − openings.
  2. Wall thickness. One unit width for a single leaf, or two widths plus a joint for a double leaf.
  3. Units per m². Using the joint-inclusive footprint of the unit face: n/m² = 1 / [(l + j)(h + j)], where l and h are the exposed face dimensions and j is the mortar joint. A double-leaf wall doubles this figure.
  4. Unit count. N = ceil(A × n/m² × (1 + wastage)). Units are always rounded up.
  5. Mortar volume. Wall volume minus the solid volume of the masonry units gives the wet mortar volume. The pre-wastage unit count is used here so mortar and units are never double-counted.
  6. Dry volume and split.Wet mortar is multiplied by CIDA's 1.30 dry-volume (bulking) factor and the wastage allowance, then split by the mix ratio 1:m, cement = dry ÷ (1 + m), sand = m × cement.
  7. Cement bags and sand. Cement volume ÷ 0.0347 m³ per 50 kg bag, rounded up. Sand volume ÷ 2.832 m³ gives cubes; × 1600 kg/m³ gives an approximate mass.

Unit sizes come from the Sri Lanka Standards Institution: SLS 855 sets the 400 × 200 mm cement-block face with 100/150/200 mm thicknesses, and SLS 39 gives the 215 × 102.5 × 65 mm reference clay brick. Because local bricks vary by kiln, the tool also offers the common 8″ × 4″ × 3″ brick and a custom size. The cement-bag volume is cross-checked two ways, by the 0.0347 m³ bag volume and by cement mass (1440 kg/m³ × a 50 kg bag), and both agree, which is the “verified two ways” note shown under the results.

Worked examples

200 mm block boundary wall

10 m × 3 m · single leaf · 1:5 · 5% wastage

  1. Face area: 10 × 3 = 30 m² (no openings)
  2. Blocks/m²: 1 ÷ (0.41 × 0.21) = 11.61
  3. Blocks: ceil(30 × 11.61 × 1.05) = 366
  4. Wall volume: 30 × 0.20 = 6.00 m³
  5. Mortar (wet): 6.00 − 5.575 = 0.425 m³
  6. Dry mortar: 0.425 × 1.30 × 1.05 = 0.580 m³
  7. Cement: 0.580 ÷ 6 = 0.097 m³ → ceil(0.097 ÷ 0.0347) = 3 bags
  8. Sand: 5 × 0.097 = 0.484 m³ = 0.17 cube (~773 kg)
  9. Result: 366 blocks · 3 cement bags · 0.17 cube sand

Half-brick internal wall

5 m × 2.5 m · SLS brick · single leaf · 1:5 · 5%

  1. Face area: 5 × 2.5 = 12.5 m²
  2. Bricks/m²: 1 ÷ (0.225 × 0.075) = 59.26
  3. Bricks: ceil(12.5 × 59.26 × 1.05) = 778
  4. Wall volume: 12.5 × 0.1025 = 1.281 m³
  5. Mortar (wet): 1.281 − 1.061 = 0.220 m³
  6. Dry mortar: 0.220 × 1.30 × 1.05 = 0.301 m³
  7. Cement: 0.301 ÷ 6 = 0.050 m³ → ceil(0.050 ÷ 0.0347) = 2 bags
  8. Sand: 5 × 0.050 = 0.251 m³ = 0.09 cube (~401 kg)
  9. Result: 778 bricks · 2 cement bags · 0.09 cube sand

Edge case, wall smaller than its openings

4 m × 3 m wall · 15 m² of openings

  1. Face area: 4 × 3 = 12 m²
  2. Openings to deduct: 15 m²
  3. Net area: 12 − 15 = −3 → clamped to 0
  4. The tool shows a clear error instead of a negative or NaN result
  5. Fix: reduce the openings, or check the units (m² vs ft²)

Frequently asked questions

Sources & references

Constants used: one 50 kg cement bag = 0.0347 m³ (Portland cement ≈ 1440 kg/m³); dry-volume factor = 1.30; sand bulk density ≈ 1600 kg/m³; one cube = 100 ft³ = 2.832 m³. Last cross-checked on 2026-07-11. This tool estimates straight, uniform-thickness walls only. It does not cover plaster, columns, tie beams or reinforcement.

Related tools

Comments & feedback

Spotted a bug or want an improvement? Tell us, our team reviews every comment, and good ideas get built. Comments are public and anonymous.

Found a bug, edge case, or want to suggest an improvement?

Email me at [email protected] , most fixes ship within 24 hours.